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对于函数：
令h_1 = 0 可以变形为：
将式1带入：h_2(t)
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=%20H_1cosh(\lambda%20t)%20-%20\frac{A_2}{\lambda}%20sinh(\lambda%20t))
-\frac{A_2}{2\lambda}(e^{\lambda%20t}+e^{-\lambda%20t})=0)
\frac{1}{e^{\lambda%20t}}%20=%20(\frac{A_2}{2\lambda}%20-%20\frac{H_1}{2})e^{\lambda%20t})
)
=%20H_2cosh(\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1}))%20-%20\frac{A_1}{\lambda}%20sinh(\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})))
=%20\frac{H_2}{2}(e^{\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})}%20+%20e^{-\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})})%20-%20\frac{A_1}{2\lambda}%20(e^{\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})}%20-%20e^{-\frac{1}{2}ln(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})})%20\\%20\indent%20\indent%20=%20\frac{H_2}{2}((\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{\frac{1}{2}}%20+%20(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{-\frac{1}{2}})%20-%20\frac{A_1}{2\lambda}((\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{\frac{1}{2}}%20-%20(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{-\frac{1}{2}})%20%20\\%20\indent%20\indent%20=%20(\frac{H_2}{2}%20-%20\frac{A_1}{2\lambda})(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{\frac{1}{2}}%20-(\frac{H_2}{2}%20+%20\frac{A_1}{2\lambda})(\frac{\frac{A_2}{\lambda}%20+%20H_1}{\frac{A_2}{\lambda}%20-%20H_1})^{-\frac{1}{2}}%20\\%20)
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